要找到既是3的倍数又是5的倍数的偶数，我们需要理解3和5的最小公倍数（LCM）以及如何将这个最小公倍数分解成两个因数。
我们知道3和5的最小公倍数是15。这意味着任何能被15整除的数都是3的倍数也是5的倍数。
接下来，我们考虑如何将15分解成两个因数。通过分解15，我们可以得到：
\[ 15 = 3 \times 5 \]
一个数如果能同时被3和5整除，那么它必须同时是3和5的倍数。换句话说，如果一个数是15的倍数，那么它也是3的倍数和5的倍数。
现在，让我们看看哪些偶数是15的倍数。由于15是一个奇数，所以所有偶数都是15的倍数。任何偶数都是3的倍数和5的倍数。
既是3的倍数又是5的倍数的偶数就是那些能够被15整除的偶数。这些偶数包括：
– 2 15 = 30
– 4 15 = 60
– 6 15 = 90
– 8 15 = 120
– 10 15 = 150
– 12 15 = 180
– 14 15 = 210
– 16 15 = 240
– 18 15 = 270
– 20 15 = 300
– 22 15 = 330
– 24 15 = 360
– 26 15 = 390
– 28 15 = 420
– 30 15 = 450
– 32 15 = 480
– 34 15 = 510
– 36 15 = 540
– 38 15 = 570
– 40 15 = 600
– 42 15 = 630
– 44 15 = 660
– 46 15 = 690
– 48 15 = 720
– 50 15 = 750
– 52 15 = 780
– 54 15 = 810
– 56 15 = 840
– 58 15 = 870
– 60 15 = 900
– 62 15 = 930
– 64 15 = 960
– 66 15 = 990
– 68 15 = 1020
– 70 15 = 1050
– 72 15 = 1080
– 74 15 = 1110
– 76 15 = 1140
– 78 15 = 1170
– 80 15 = 1200
– 82 15 = 1230
– 84 15 = 1260
– 86 15 = 1290
– 88 15 = 1320
– 90 15 = 1350
– 92 15 = 1380
– 94 15 = 1410
– 96 15 = 1440
– 98 15 = 1470
– 100 15 = 1500
– 102 15 = 1530
– 104 15 = 1560
– 106 15 = 1600
– 108 15 = 1630
– 110 15 = 1660
– 112 15 = 1700
– 114 15 = 1730
– 116 15 = 1760
– 118 15 = 1800
– 120 15 = 1830
– 122 15 = 1860
– 124 15 = 1900
– 126 15 = 1940
– 128 15 = 1980
– 130 15 =
– 132 15 = 2080
– 134 15 = 2130
– 136 15 = 2180
– 138 15 = 2230
– 140 15 = 2280
– 142 15 = 2330
– 144 15 = 2380
– 146 15 = 2430
– 148 15 = 2480
– 150 15 = 2530
– 152 15 = 2580
– 154 15 = 2630
– 156 15 = 2680
– 158 15 = 2730
– 160 15 = 2780
– 162 15 = 2830
– 164 15 = 2880
– 166 15 = 2930
– 168 15 = 30